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kyleeeeee94
16.03.2020 •
Mathematics
Find the average value of f(x)=e^2x-2 on the interval [0,2].
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Ответ:
Step-by-step explanation:
f(0)=e^0-2=1-2=-1
f(1)=e²-2
f(2)=e^4-2
average value=(`-1+e²-2+e^4-2)/3=(e^4+e²-5)/3
Ответ:
what does the rest say?