Shiey0409
15.07.2019 •
Mathematics
Find the cosine of the angle between the planes 4x−1y+2z=−4 and the plane 1x+1y−4z=3.
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Ответ:
Try this solution:
1. Given: α:4x-y+2z=-4 and β:x+y-4z=3.
if vector n₁⊥α and n₂⊥β, then required cosine is:
where n₁*n₂=4*1+(-1)*1+2*(-4) and |n₁|*|n₂|=√(4²+1²+2²)*√(1²+1²+4²).
2. Using the formula of cosine:
≈0.2572
Ответ:
Thanks for the points :3