Mathematics: Find the cotangent, cosine, and tangent of both angles a and b. if you could put it in this format: cotangent - cosine - tangent - that would be epic : ^d

Find the cotangent, cosine, and tangent of both

Ответ:

PermanentJetlag

10.01.2022

$\displaystyle \frac{5}{12} = cot∠B \\ 2\frac{2}{5} = cot∠A \\ \\ 2\frac{2}{5} = tan∠B \\ \frac{5}{12} = tan∠A \\ \\ \frac{5}{13} = cos∠B \\ \frac{12}{13} = cos∠A$

Step-by-step explanation:

$\displaystyle \frac{OPPOSITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOSITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOSITE} = csc\:θ \\ \frac{ADJACENT}{OPPOSITE} = cot\:θ \\ \\ \frac{10}{24} = cot∠B → \frac{5}{12} = cot∠B \\ \frac{24}{10} = cot∠A → 2\frac{2}{5} = cot∠A \\ \\ \frac{24}{10} = tan∠B → 2\frac{2}{5} = tan∠B \\ \frac{10}{24} = tan∠A → \frac{5}{12} = tan∠A \\ \\ \frac{10}{26} = cos∠B → \frac{5}{13} = cos∠B \\ \frac{24}{26} = cos∠A → \frac{12}{13} = cos∠A$

I am joyous to assist you anytime.

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Ответ:

mahmudabiazp3ekot

29.08.2020

Mathematics

About 3.6 times greater.

Step-by-step explanation:

That is 1.793 * 10^8 / 5.01 * 10^7

= 1.793 / 5.01 * 10^(8-7)

= 0.36 * 10

= 3.6

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Find the cotangent, cosine, and tangent of both angles a and b.

if you could put it in this format:

cotangent -

cosine -

tangent -

that would be epic : ^d

Ответ:

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