kuadirkennedy
12.07.2019 •
Mathematics
Find the density function of y = ez , where z ∼ n(µ, σ2). this is called the lognormal density, since log y is normally distributed.
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Ответ:
Y = e^2 -> ln y = z [e^2 > 0 -> y > 0]
Fy (y) = P (Y ≤ y)
= P (e^2 £ y)
= P (Z ≤ ln y)
= Fx (ln y)
Differentiating, fy (y) = 1/y fz (ln y)
= 1/y * [(1 / σ sqrt of 2π) e^(1/2 ((ln y - µ)/a)^2)] , y > 0
Which is the required density function of y = e^2
Ответ:
She can buy 5 pounds of apples.
Step-by-step explanation: