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maddylol3863
03.07.2019 •
Mathematics
Find the difference of functions s and r shown below. r(x) = –x² + 3x s(x) = 2x + 1 (s – r)(x) =-x^2+3x-2x+1(-x^2+3x)-2x+1(2x+ + 3x)2x+1-x^2+3x
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Ответ:
The difference of the function is (2x+1)-(x^2 + 3x)
Difference of functionsGiven the following functions
r(x) = –x² + 3x
s(x) = 2x + 1
Taking the difference of the function will give:
(s – r)(x) = 2x - 1 - (-x^2 + 3x)
Expand
(s – r)(x) = 2x - 1 + x^2 - 3x
(s – r)(x) = x^2 - x - 1
Hence the difference of the function is (2x+1)-(x^2 + 3x)
Learn more on difference of functions: link
Ответ:
(2x + 1) - (–x² + 3x) is difference .
Step-by-step explanation:
Given : r(x) = –x² + 3x and s(x) = 2x + 1
To find : Find the difference of functions s and r .
Solution : We have given that r(x) = –x² + 3x and s(x) = 2x + 1.
Difference :
(s – r)(x) = s(x) - r(x)
=(2x + 1) - (–x² + 3x)
= 2x +1 + x²-3x
= x²-x +1.
Therefore, (2x + 1) - (–x² + 3x) is difference .
Ответ:
Her answer is incorrect. At first glance 30/29 is greater than 1. When you multiply 60 by something greater than 1, the answer is going to be greater than 60.
Step-by-step explanation:
60(30/29) = 1800/29 = 62.07