Find the equation of a line parallel to y=2x-4 that contains the points (5,1)

The correct answer is
y=2x-9

Since the lines are parallel, they will gave the same slope (in this case it’s 2)

Our equation will be
y=mx+b

We know the slope is 2, and they’ve given us x and y coordinates. Plugging it in to the slope equation we get

1=2(5)+b

1=10+b

Subtract 10 from both sides and you get

-9=b

Putting it together our new parallel line will be

y = 2x - 9

16 km due west

Step-by-step explanation:

The bearing of the school p from school q is 16 km due west.

To find the bearing of school q from school p, we have to find the direction that the school q is with respect to school p.

Since p is directly west of q, then it implies that q must be directly east of p.

We now know the direction.

Since the distance from q to p is exactly the same as the distance from p to q, then, the distance from p to q is 16 km.

Hence, the bearing of q from p is 16 km due west.