Find the equation of the line passing through the - id1014463, aminamuhammad11

Question

Mathematics: Find the equation of the line passing through the points (-2/3,1) and (-2,1/2). write the equation in standard form.

aminamuhammad11 · Accepted Answer

x-intercept is the point where a line crosses the x-axis.

y-intercept is the point where a line crosses the y-axis.

(A)

y=2x+1

Set y =0 to solve for x;

2x+1=0

⇒ $x=-\frac{1}{2}$

x- intercept of the line is; ( $-\frac{1}{2}$ , 0)

Set x= 0 to solve for y;

$y= 2\cdot 0+1$

y=0+1=1

then, y-intercept is, (0,1).

(B)

y = -0.5x+1

Same process for B as we have done in (A);

x-intercept = (2,0)

y-intercept = (0,1)

(C)

y= -2x-1

x-intercept = ( $-\frac{1}{2}$ , 0)

y-intercept = (0,-1)

(D)

y= -2x+1

x-intercept = ( $\frac{1}{2}$ , 0)

y-intercept = (0,1)

(E)

y =0.5x+1

x-intercept = (-2,0)

y-intercept = (0,1)

(F)

y = 2x-1

x-intercept = ( $\frac{1}{2}$ , 0)

y-intercept = (0,-1).

So the answer for this is shown in the attachment below;

Find the equation of the line passing through the points (-2/3,1) and (-2,1/2). write the equation in standard form.