kemellgwilson
12.02.2021 •
Mathematics
Find the expected value of the random variable with the following probability distribution
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Ответ:
D. y + 3 = 3/5 (x-6)
Step-by-step explanation:
considering equation D
when x = 6
R.H.S. = 3/5 (x-6)
= 3/5 (6-6)
= 0
when y= -3
L.H.S. = y + 3
= -3 + 3
= 0
line passes through (6,-3)
Like that we can prove it's passing through (-4,-9)