Find the laplace transform of the function f(t) = sin^2 t

Alright
the points of f(x) are
(-1,-6)
(0,-3)
(1,0)

and g(x)=4x-5

A.
find f(x)'s slope
the slope of the line passing through the points (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)
so 2 points are (0,-3) and (1,0), so the slope is (0-(-3))/(1-0)=(0+3)/(1)=3/1=3
the slope of f(x) is 3

g(x)'s slope
y=mx+b
m=slope
so, given
g(x)=4x-5
4 is the slope
g(x)'s slope is 4

B.
the y intercept is the value when x=0
for f(x)
remember: (x,y)
notice we have the point (0,-3)
so the y intercept of f(x) is y=-3

for g(x)
y=mx+b
b=y intercept
g(x)=4x-5
the y intercept of g(x) is y=-5

f(x) has the greater y intercept because -3>-5