Mathematics: Find the length of the curve x=1−t,y=t−5,z=2t−2, for 1≤t≤3

Find the length of the curve x=1−t,y=t−5,z=2t−2,

Ответ:

smesarahmitchell

15.01.2022

To find length of curve use:
$\int\limits^a_b {|r'(t)|} \, dt$
where r(t) is vector equation:
r(t) = (1,-5,-2) + (-1,1,2)t

Magnitude of vector r'(t) is then:
$\sqrt{(-1)^2 +1^2 +2^2} =\sqrt{6}$
Now evaluate integral
$\int\limits^3_1 {\sqrt{6}} \, dt = \sqrt{6} (3-1) = 2 \sqrt{6}$

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Ответ:

yoda78

12.01.2022

Mathematics

equals 3x(9v+23x95=12.84953029393

Step-by-step explanation:

figure it out ur smart

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Find the length of the curve

x=1−t,y=t−5,z=2t−2,

for 1≤t≤3

Ответ:

Ответ:

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