Find the measurements of ∠CQD and ∠EQF. *

m ∠CQD = 11; m∠EQF = 11

m ∠CQD = 20; m∠EQF = 30

m ∠CQD = 11; m∠EQF = 3

m ∠CQD = 22x; m∠EQF = 33x

m ∠CQD = 33x; m∠EQF = 22x

m ∠CQD = 33; m∠EQF = 22

m ∠CQD = 4; m∠EQF = 6

m ∠CQD = 2x + 11; m∠EQF = 3x + 11

m ∠CQD = 22; m∠EQF = 33

Correct option: ninth one.

m∠CQD = 22°

m∠EQF = 33°

Step-by-step explanation:

as the segment BQG is a straight line, its angle is 180 degrees, so the sum of all those 5 angles is equal to 180 degrees. So, we have that:

m∠FQG + m∠EQF + m∠DQE + m∠CQD + m∠BQC = 180°

12 + 3x + 103 + 2x + 10 = 180

5x + 125 = 180

5x = 55

x = 11°

Then, we have that:

m∠CQD = 2x = 22°

m∠EQF = 3x = 33°

These Lines will be parallel.

Step-by-step explanation:

You have to find the slope of each line. For (1,1) and (3,3) the slope is 1 and for Line 2 the slope is also 1. (let me know if you want me to show the work for slope). To have parallel lines the slopes have to be the same and y-ints have to be different. Here the slopes are the same and in Line 1 the yint is (0,0) which is different than Line 2. Therefor the Lines are parallel.  

Sorry if im wrong!. Hope this helps