Find the missing dimension of the cone

h=1ft

Step-by-step explanation:

The volume of a cone is:

v=πr^h/3

plug in the values (I am assuming not 1/18π but 1/18×π):

1/18π=  π1/3^2h/3

Get rid of the radius:

1/3^2=1/9

Continue:

π/18= πh/3*1/9= πh/18

Remove the denominators:

π=πh

Divide both sides by π :

h=1

The temperature would be 87.21 degrees Celsius (4s.f)

Step-by-step explanation:

P1 = 258mmHg

T1 = 22.0 degrees Celsius

= 295.15 K

P2 = 315mmHg

Since mmHg is directly proportional to pa, no conversion is required in this case, as they would cancel.

T2 = ?

P1/T1 = P2/T2

T2 = P2T1/P1

= 315(295.15)/258

= 360.36 K

= 87.21 degrees Celsius (4s.f)