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jonnycampbell223
06.07.2020 •
Mathematics
Find the probability of rolling a sum of 10 or a sum that is an odd number when two number cubes are rolled.
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Ответ:
7/12 chance
Step-by-step explanation:
(1 2 3 4 5 6)
(1 2 3 4 5 6)
All the possibilities:
(1, 1) (2, 1) (3, 1) (4, 1) (5, 1) (6, 1)
(1, 2) (2, 2) (3, 2) (4, 2) (5, 2) (6, 2)
(1, 3) (2, 3) (3, 3) (4, 3) (5, 3) (6, 3)
(1, 4) (2, 4) (3, 4) (4, 4) (5, 4) (6, 4)
(1, 5) (2, 5) (3, 5) (4, 5) (5, 5) (6, 5)
(1, 6) (2, 6) (3, 6) (4, 6) (5, 6) (6, 6)
There are 18 odd sums.
(1, 1) (2, 1) (3, 1) (4, 1) (5, 1) (6, 1)
(1, 2) (2, 2) (3, 2) (4, 2) (5, 2) (6, 2)
(1, 3) (2, 3) (3, 3) (4, 3) (5, 3) (6, 3)
(1, 4) (2, 4) (3, 4) (4, 4) (5, 4) (6, 4)
(1, 5) (2, 5) (3, 5) (4, 5) (5, 5) (6, 5)
(1, 6) (2, 6) (3, 6) (4, 6) (5, 6) (6, 6)
There are 3 possibilities whose sums add up to 10.
Since there are 36 total possibilities and 21 numbers that fit the rule of having an odd sum or a sum of 10. There is a 21/36 chance or simplified, 7/12 chance.
Ответ:
No solution
Explanation
−x^2+5x−10=0
Step 1: Use quadratic formula with a=-1, b=5, c=-10.
you plug it in as shown below
and simplify
when you simplify
you get
as shown below
This is no solution....