Mathematics: Find the product. 3y 2 z(2y 2 z + 4yz - y + z) a 4y 6z 2 + 13y 3z 12 - 3y 2z 2 - 3yz b 6y 4z 2 + 12y 3z 2 - 3y 3z + 3y 2z 2 c 6y 2z 4 - 12y 2z 3 + 3yz 3 - 3y 2z 2 d 3y 4z 2 + 3y 3z 2 - 6y 3z - 4

Find the product. 3y 2 z(2y 2 z + 4yz - y + z) a

Ответ:

Aliciaonfleek

17.01.2022

Answer :

$6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3 {y}^{3} {z}+3 {y}^{2} {z}^{2}$

Step-by-step explanation :

To find the product of

$3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)$

First we expand the bracket ,

it implies that, we use the expression outside the bracket to multiply individual expressions inside the bracket.

Hence

$3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)$

$= 3 {y}^{2} z(2 {y}^{2} z) + 3 {y}^{2} z(4yz) - 3 {y}^{2} z(y )+3 {y}^{2} z( z)$

we now apply the law of indices

${a}^{m} \times {a}^{n} = {a}^{m+n}$

meaning, when you are multiplying two expressions with the same bases , repeat one of the bases and add the exponents.

Then, simplify to obtain

$= 6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3{y}^{3} {z}+3 {y}^{2} {z}^{2}$

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Ответ:

claudia122752

08.10.2021

Mathematics

Sorry, that really sucks

Step-by-step explanation:

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Find the product.

3y 2 z(2y 2 z + 4yz - y + z)

a 4y 6z 2 + 13y 3z 12 - 3y 2z 2 - 3yz

b 6y 4z 2 + 12y 3z 2 - 3y 3z + 3y 2z 2

c 6y 2z 4 - 12y 2z 3 + 3yz 3 - 3y 2z 2

d 3y 4z 2 + 3y 3z 2 - 6y 3z - 4

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