Find the slope-intercept form of an equation for the line that passes through (-1,2) and is parallel to y=2x-3

y = 2x+4

Step-by-step explanation:

The slope of the line y = 2x-3  is 2

(y=mx+b  where m is the slope)

We want a line that is parallel.  Parallel lines have the same slope.  So the slope of the new line is 2.

We have the slope =2 and a point (-1,2).   We can use point slope form to make an equation

y-y1 = m(x-x1)

y-2 = 2(x--1)

y-2 = 2(x+1)

Distribute the 2

y-2 =2x+2

Add 2 to each side

y-2+2 = 2x+2+2

y = 2x+4

This is in slope intercept form

(0,-4)

Step-by-step explanation:

4x-2y=8

y=-4-3x

4x-2(-4-3x)=8

x=0

y=-4-3x0

y=-4