rimcdaniel2
30.06.2019 •
Mathematics
Find the slope of the tangent line to the curve y=2/(x+3) at the point where x=a
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Ответ:
the slope of the tangent is the derivate for : y when x = a
y=2/(x+3)
y' = - 2 / (x+3)²
x = a y' = -2/(a+3)²
the slope is : -2/(a+3)²
Ответ:
Step-by-step explanation:
the equation is:
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