Find the sum of 13 sigma i=5 3i+2 a 261 b 41 c 220 d 38

Hello!

You put numbers from 5 to 13 in for i and add all the values up

3(5) + 2 = 17
3(6) + 2 = 20
3(7) + 2 = 23
3(8) + 2 = 26
3(9) + 2 = 29
3(20) + 2 = 32
3(11) + 2 = 35
3(12) + 2 = 38
3(13) + 2 = 41

Now add all the numbers up

17 + 20 + 23 + 26 + 29 + 32 + 35 + 38 + 41 = 261

The answer is A) 261

Hope this helps!

on the 24th day they both will make chocolate the LCM of 8 and 12 is 24