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10.12.2020 •
Mathematics
Find the value of functions f(x)=2x^2-3x+ given x=3x-5
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Ответ:
Step-by-step explanation:
f(x) =2x^2 - 3x
f(3x -5) = 2(3x -5)^2 - 3(3x -5)
2 x 3x = 6x and 2 x -5 = -10
f(3x -5) = (6x -10)^2 - 3(3x -5)
-3 x 3x = -9x and 3 x -5 = -15
f(3x -5) = (6x -10)^2 - (-9x -15)
That's all I know ;-;- I forgot how to finish it
Ответ:
no solutions
Step-by-step explanation: