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allyssaharrisooy50au
16.06.2020 •
Mathematics
Find the values of a, b and c in the equation below (x^5yz^4)^3/x^3yz= x^a y^b z^c
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Ответ:
a = 12, b = 2, c = 11
Step-by-step explanation:
Using exponent rules we can distribute the exponent of 3 to the xyz.
This results in the numerator now being.
This can be simplified to,
.
Now divide the numerator by the denominator subtracting the exponents.
Which equals,![x^{12}y^{2}z^{11}](/tpl/images/0686/7729/78c35.png)
So a = 12
b = 2
and
c = 11
Ответ:
give me a second, i will answer but i just need some points real quick
Step-by-step explanation: