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Sanyam231
08.07.2019 •
Mathematics
Find the values of m for which the lines y=mx-2 are tangents to the curve with equation y=x^2-4x+2
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Ответ:
Let y= mx-2 be the tangent line to y=x^2-4x+2 at x=a.
Then slope,![m=\frac{dy}{dx} at x=a = 2a-4.](/tpl/images/0067/2770/e8c9d.png)
Hence the equation is y=(2a-4)x-2
Let's find y-coordinate at x=a using tangent line and curve.
Using tangent line y at x=a is (2a-4) a -2![=2a^{2}-4a-2](/tpl/images/0067/2770/7d7fb.png)
Using given curve y-coordinate at x=a is![a^{2}-4a+2](/tpl/images/0067/2770/334a0.png)
Let's equate these 2 y-coordinates,
a=2 or -2.
If a=2,![m=2a-4 = 2*2-4=0](/tpl/images/0067/2770/1b9c1.png)
If a=-2,![m= 2(-2)-4 = -8](/tpl/images/0067/2770/6a160.png)
Hence m values are 0 and -8.
Ответ: