Find the values of the trigonometric functions of t from the given information. cos(t) = − 8 17 , terminal point of t is in quadrant iii

Find the value of the trigonometric function of t form the given information

Cost=-8/17,terminal point of t is in quadrant 3rd in which cos<0, sin<0

Sint=-√(1-cos^2t)=-√(1-64/289)

=-√(225/289)=-15/17

Tant =sin/cos= -15/-8=15/8

Csc t=-17/15

Sect =-17/8

Cot=8/15

y = -x + 2

Step-by-step explanation:

First, find the slope.

12 - (-3) / -10 - 5

15/-5

-1

The slope is -1.

Our equation will be y = -1x + b

Insert on the x,y corrdinates given.

12=-1(-10) + b

12=10 + b

2 = b

Now that we know b,

the equation is

y = -x + 2