Find the x-intercepts (solve for x) for the following and show your work! y=−2x^2−9x+5

see explanation

Step-by-step explanation:

To find the x- intercepts set y = 0, that is

- 2x² - 9x + 5 = 0

To factorise the quadratic consider the factors of the product of the coefficient of the x² term and the constant term that sum to give the coefficient of the x- term.

product = - 2 × 5 = - 10 and sum = - 9

The factors are - 10 and + 1

Use these factors to split the middle term

- 2x² - 10x + x + 5 = 0 ( factor the first/second and third/fourth terms )

- 2x(x + 5) + 1(x + 5) ( factor out (x + 5) )

(x + 5)(- 2x + 1) = 0

equate each factor to zero and solve for x

x + 5 = 0 ⇒ x = - 5

- 2x + 1 = 0 ⇒ x =

x-intercepts are x = - 5 and x =

1/7

Step-by-step explanation:

negative reciprocal