ashantiwilliams11120
20.10.2019 •
Mathematics
Find the zeros of this polynomial function?
f(x)=6x^2 + 4x + 8
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Ответ:
Δ=4²-6*8<0 ==> no real zeroes.
but f(x)=6*(x+(-1-i√2)/3)(x+(-1+i√2)/3 )
Ответ:
Step-by-step explanation: