OGrant18075
19.09.2019 •
Mathematics
Find three consecutive odd integers that the sum of the first, two times, the second, and three times the third is 70
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Ответ:
Given,
(x - 2) + 2x + 3(x + 2) = 70
x - 2 + 2x + 3x + 6 = 70
6x + 4 = 70
6x = 66
x = 11
Hence, the integers are 9, 11 and 13.
Ответ:
D: all real numbers greater than or equal to –3
Step-by-step explanation:
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