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Rboltonbcs
12.09.2019 •
Mathematics
Find two consecutive odd integers such that 77 more than the lesser is six times the greater.
the lesser consecutive odd integer is _ and the greater consecutive odd integer is _
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Ответ:
The answer to your question is : number 1 = 13 number 2 = 15
Step-by-step explanation:
# 1 = 2n +1
# 2 = 2n +3
Conditions:
2n + 1 + 77 = 6(2n + 3)
Simplify 2n + 78 = 12 n + 18
Solve it for n 12n - 2n = 78 -18
10n = 60
n = 60/10
n = 6
But
# 1 = 2n + 1 = 2(6) + 1 = 12 + 1 = 13
# 2 = 2n + 3 = 2(6) + 3 = 12 + 3 = 15
Ответ:
u
Step-by-step explanation: