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trentonthreats5073
05.08.2019 •
Mathematics
Five males with an x-linked genetic disorder have one child each. the random variable x is the number of children among the five who inherit the x-linked genetic disorder. determine whether a probability distribution is given. if a probability distribution is given, find its mean and standard deviation. if a probability distribution is not given, identify the requirements that are not satisfied.
x p(x)
0 0.029
1 0.147
2 0.324
3 0.324
4 0.147
5 0.029
a. does the table show a probability distribution?
b. find the mean of the random variable x.
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Ответ:
Answer and Explanation:
Given : Five males with an X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the X-linked genetic disorder.
To find :
a. Does the table show a probability distribution?
b. Find the mean and standard deviation of the random variable x.
Solution :
a) To determine that table shows a probability distribution we add up all six probabilities if the sum is 1 then it is a valid distribution.
Yes it is a probability distribution.
b) First we create the table as per requirements,
x P(x) xP(x) x² x²P(x)
0 0.029 0 0 0
1 0.147 0.147 1 0.147
2 0.324 0.648 4 1.296
3 0.324 0.972 9 2.916
4 0.147 0.588 16 2.352
5 0.029 0.145 25 0.725
∑P(x)=1 ∑xP(x)=2.5 ∑x²P(x)=7.436
The mean of the random variable is
The standard deviation of the random sample is
Therefore, The mean is 2.5 and the standard deviation is 1.08.
Ответ:
(2.6, -2.7)
Step-by-step Explanation:
Let X represent the point which is 7/10 of the way from A to B.
AX to XB = 7:10 = AX/XB = 7/10.
Formula for internal division to find the coordinates is:
Where,
Substitute the values above into the stated formula to find x and y coordinates as follows:
The coordinates of the point 7/10 of the way from A to B are (2.6, -2.7)