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laneycasey9058
09.06.2021 •
Mathematics
For the function f(x) = -12x^2 + 6x - 8 find the equation of the tangent line at x= -1
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Ответ:
Substitute x = -1 in f(x) we get y = -26
y = -12x^2+6x-8
Differentiate ‘y’ w.r.t ‘x’ we get
dy/dx = -24x+6
By putting value of ‘x’ we get
dy/dx = 30
Slope(m)=dy/dx = 30
Equation of tangent => (y - y1)=m(x - x1)
Here, x1= -1 and y1 = -26 and m = 30
So, (y - (-26)) =30(x - (-1))
y+26=30(x+1)
y+26=30x+30
30x - y + 4 =0 is the equation of tangent at x = -1
Ответ:
just divide and you will get the decimal =)