For what value(s) of k will the given relation not be a function? M = { (15k+9, 4), (3·(4k−1), 6) }

Enter all possible values of k

Given:

The relation is

To find:

The value of k for which the relation is not a function.

Solution:

A relation is a function if their exist a unique output or y value for each input or x values.

A relation is not a function if it has two y-values for single x value.

So, the given relation is not a function if x-coordinates of both ordered pairs are equal.

Isolate variable terms.

Divide both sides by 3.

Therefore, the given relation is not a function for k=-4.

the lengths of the bases of the trapezoids are
trapezoid A
b=19cm, and B=35cm, b the short base and B the long base

trapezoid B
b=19cm, and B=35cm, b the short base and B the long base

the height is h=15cm

the surface of A is A= hx(b+B) /2

so the surface is A= 15(19+35)/2=405cm²
we know that suface A =surfaceB, so Surface B= 405cm²

finally the total surface painted is 2 x 405cm²= 810cm²

the perimeter of the trapezoid A is PA=17+19+35+17=88cm
the perimeter of the trapezoid B is PB=17+19+35+17=88cm

 one piece of sandpaper will not be enough to sand the edges of one trapezoid