harvzoie
13.08.2020 •
Mathematics
For what values of k will the function y=6x^2-8x+k have one zero: Two zeros: No zeros
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Ответ:
Step-by-step explanation:
consider 6x^2-8x +k
disc .=(-8)^2-4*6*k=64-24k
it has no solution if 64-2k<0
or 64<2k
or 2k>64
k>32
it has two zeros if 64-2k≥0
or 64≥ 2k
or 2k≤64
or k≤ 32
it has one zero if Disc. =0
64-2k=0
2k=64
k=32
Ответ:
value of y =0 so x axis
Step-by-step explanation: