Given: abcd is a rhombus,
perimeter = 20,
ac: bd = 4: 3 find:
area of abcd.

4a=20⇒a=5

we know diagonals are perpendicular. if u look at one of the right triangles, you can see that for hypotenuse to be 5, the legs have to be 4 and 3 to satisfy the given ratio 4:3.

so, diagonals are 8 and 6 as we know that diagonals bisect each other.

Area=8*6/2=24

P(anb) it askes what is the probability of event a to happen and also event b) so you need to use multipication since for both to happen you need the first to happen and then the second too0.4•0.9=.36