Given: AE = BD; CD = CE

Prove AC = BC

Step-by-step explanation:

Funny question!

AE=BD

A= BD/E

Then,

CD=CE

D=E

therefore, A=BE/E (SINCE, D=E)

So, A=B

or, AC= BC (multiplying by C)

We are asked to transform the given equation into slope intercept form. The given expression is 2-3y+6x=0. To do this, we need to remember the slope-intercept form is below:
y = mx + b where "m" represents the slope and "b" represents the y-intercept

The solution of the problem is shown below:
2 - 3y + 6x = 0 ,transpose -3y to the opposite side such as:
2 + 6x = 3y , re-arranging the given we have:
3y = 6x + 2 , divide both sides by 3 such as:
3y/3 = (6x +2) / 3
y = 2x + 2/3 where m = 2 and b = 2/3

The answer is y = 2x + 2/3.