arnold2619
22.10.2020 •
Mathematics
Given f\left(x\right)=\frac{1}{3}\left(4-x\right)^2f(x)=
3
1
(4−x)
2
, what is the value of f(16)?
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Ответ:
-9.661
Step-by-step explanation:
-a+(-b)
a= 6.05 b=3.611
calculate the difference:
-6.05+(-3.611)= -9.661