deijiahshatia
04.11.2019 •
Mathematics
given p(a) = 0.072, p(b) = 0.180, and p(c) = 0.027, and that events a, b, and c are mutually exclusive, what is the p(a or b or c)?
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Ответ:
Given P(A) = 0.072, P(B) = 0.180, and P(C) = 0.027, and that events A, B, and C are mutually exclusive,then P(A or B or C) is 0.279
Solution:
Given that probability of event A is P(A) = 0.072
Probability of event B is P(B) = 0.180
Probability of event C is P(C) = 0.027
Also event A, B and C are mutually exclusive.
Need to determine P( A or B or C )
For mutually exclusive events
P( A or B or C ) = P(A) + P(B) + P(C)
= 0.072 + 0.180 + 0.027 = 0.279
Hence probability of occurrence of event A or event B or event C , where A , B and C are mutually exclusive events is 0.279.
Ответ:
50/-25= -2
-2 x 4= -8
Sorry I realized I put 24 Oops...
But Ctapia037 is right.