Given the following formula, solve for y. W = x-y/2 - z A.) Y= 2(w + z) - x
B.) y = x– (2w + z)
C.) Y = x – (2W + z)
D.) Y= 2w + 2 - z - x

the answer is B. y=x-(2w+z)

Step-by-step explanation:

    for the right-hand side, use cosine double angle identity which states that  cos 2x = cos²x - sin² x    for the left-hand side    we factor using difference of squares.recall difference of squares factoring: a² - b² = (a - b)(a + b)but here we have a⁴ - b⁴, so  a⁴  - b⁴ = (a² - b²)(a²  + b²)note that cos⁴ x is equivalent to (cos x)⁴ and etc.    note that cos²x + sin²x = 1 via the pythagorean identity