Given y=2/3x-2, write an equation whose graph is steeper and shifted to the right 5 units and reflected. Please help me understand

Step-by-step explanation:

You are given y= (2/3)x - 2, which is the equation of a straight line with slope (2/3) and y-intercept -2.  

If you wish to increase the slope (make the graph steeper), replace the given slope (2/3) with 1 (which is greater than 2/3).  Then we have

y=2/3x-2

If we translate the entire graph to the right by 5 units, we get:

y= 1(x - 5) - 2

If we reflect this new graph about the x-axis, we get:

y = -(x - 5) + 2

If necessary, repost your question after specifying whether you're to reflect this graph of y= x - 2 about the x-axis or about the y-axis.

The line passing through the origan (Graph 2 on Edu is correct.)

Step-by-step explanation: