Giving away all my points if someone answer this question look in attachment

40log5(x)
In a log equation, you can move the exponent down in front of the log and multiply it by that number instead of using an exponent

The problem is looking for the area of the trapezoid. To solve for the area of a trapezoid, we can cut them into different shapes like rectangle and triangles.

First, we draw altitudes at M and L to make a rectangle with length 22 ft and width 17 ft. We subtract 22 ft from 32 ft and divide it by 2 in order to get the base for each triangle.
(32-22)/2 = 5 ft.

Next, we find the area of the rectangle. A = LW = 22 ft x 17 ft = 374 ft^2.

Then we find the area of the triangle: A = 0.5BH = 0.5 x 5 ft x 17 ft = 42.5 ft^2

Total area = 374 ft^2 + 2(42.5 ft^2) = 459 ft^2.
The answer is D.