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c. 3727 meters

Step-by-step explanation:

Given;

the chemical had spread 1500 meters from its source.

At n=1, x1 = 1500 m

After two years, the chemical had spread 900 meters more.

At n=2, x2 = 900 m

and by the end of the third year, it had reached an additional 540 meters

At n = 3, x3 = 540 m

The chemical spread for the three years can be used to form a geometric progression G.P.

First term a = x1 = 1500 m

Common ratio r = x2/x1 = 900/1500 = 0.6

number of terms n = 10 years

Sum of nth term of a GP;

S(n) = a(1 - r^n)/(1 - r) (since r < 1)

Substituting the given values;

S(10) = 1500(1−0.6^10)÷(1-0.6)

S(10) = 3727.325184 = 3727 meters

After 10 years it would have spread 3,727 meters