Mathematics: Graphing help please! 25 points!

Graphing help please! 25 points! - id255965253, JebKush3161

ayoismeisalex

23.01.2022

Answer and Step-by-step explanation:

Let's plug in each of -2, -1, 0, 1, and 2 in for x in the equation f(x)=(1/2)^x .

f(-2) = $(1/2)^{-2}=4$ ----- So, plot the point (-2, 4)

f(-1) = $(1/2)^{-1}=2$ ------- So, plot the point (-1, 2)

f(0) = $(1/2)^{0}=1$ ------ So, plot the point (0, 1)

f(1) = $(1/2)^{1}=1/2$ ----- So, plot the point (1, 1/2)

f(2) = $(1/2)^{2}=1/4$ ------- So, plot the point (2, 1/4)

After plotting those points, just connect the dots and that's your graph.

Hope this helps!

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tia0625

23.01.2022

Join the points found below using a curve

Step-by-step explanation:

f(x) = (½)^x

x = -2, f(x) = 4

x = -1, f(x) = 2

x = 0, f(x) = 1

x = 1, f(x) = ½

x = 2, f(x) = ¼

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tusharchandler124

20.06.2022

By definition of the derivative,

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{(s + h)^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{s^3+3s^2h+3sh^2+h^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\frac{3s^2h+3sh^2+h^3}2}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 \frac{3s^2h+3sh^2+h^3}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 (3s^2+3sh+h^2)$

$\displaystyle\frac{dr}{ds} = \frac{3s^2}2$

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