Mathematics: Helen is putting a fence around her flower garden, which is in the shape of half of a circle and a rectangle. If the semicircle has a diameter of 7 feet and the rectangle has a width of 10 feet, how much fencing will Helen need? A rectangle has a length of 10 feet and width of 7 feet. A semicircle has a diameter of 7 feet. What is the perimeter around the three sides of the rectangular section of the garden? What is the approximate distance around half of the circle? (Use pi = StartFraction 22 over

Helen is putting a fence around her flower garden,

proutyhaylee

21.01.2022

Part 1) Helen will need 38 feet of fencing

Part 2) The perimeter around the three sides of the rectangular section of the garden is 27 feet

Part 3) The approximate distance around half of the circle is 11 feet

Step-by-step explanation:

Part 1) How much fencing will Helen need?

Find out the perimeter

we know that

The perimeter of the figure is equal to the sum of three sides of the rectangular section plus the circumference of a semicircle

$P=2L+W+\frac{1}{2}\pi D$

we have

$L=10\ ft\\W=7\ ft\\D=7\ ft\\\pi =\frac{22}{7}$

substitute

$P=2(10)+7+\frac{1}{2}(\frac{22}{7})(7)$

$P=20)+7+11=38\ ft$

therefore

Helen will need 38 feet of fencing

Part 2) What is the perimeter around the three sides of the rectangular section of the garden?

P=2L+W

we have

$L=10\ ft\\W=7\ ft$

substitute

P=2(10)+7

$P=20+7=27\ ft$

therefore

The perimeter around the three sides of the rectangular section of the garden is 27 feet

Part 3) What is the approximate distance around half of the circle?

Find the circumference of semicircle

$C=\frac{1}{2}\pi D$

we have

$D=7\ ft\\\pi =\frac{22}{7}$

substitute

$C=\frac{1}{2}(\frac{22}{7})(7)$

$C=11\ ft$

therefore

The approximate distance around half of the circle is 11 feet

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