Mathematics: Help is much appreciated

3x + y = 9 (I)y = –4x + 10 (II)------------------------Pass the incognito 4x to the first term, changing the signal when changing sides.-------------------------simplify by (-1)-------------------------------------------------------------Substitute in equation (I) to find the value of Y .3x + y = 9 (I)3*(1) + y = 93 + y = 9y = 9 - 3...

Help is much appreciated - id12290200, shygrl05

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TravisI00

29.04.2021

Mathematics

im stuck on this 2

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i cant help :(

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Ответ:

savyblue1724707

30.10.2020

Mathematics

3x + y = 9 (I)
y = –4x + 10 (II)
------------------------
$\left \{ {{3x + y = 9 } \atop {y = -4x + 10 }} \right.$

Pass the incognito "4x" to the first term, changing the signal when changing sides.
-------------------------
simplify by (-1)
$\left \{ {{3x + y = 9.(-1)} \atop {4x + y = 10 }} \right.$

-------------------------
$\left \{ {{- 3x - \diagup\!\!\!\!y =-9} \atop {4x + \diagup\!\!\!\!y = 10}} \right. 
$

-------------------------
$\left \{ {{- 3x = - 9} \atop {4x = 10}} \right.$

-----------
$\boxed{x = 1}$

Substitute in equation (I) to find the value of "Y".

3x + y = 9 (I)
3*(1) + y = 9
3 + y = 9
y = 9 - 3
$\boxed{y = 6}$

$\boxed{\boxed{ \left \ {{x=1} \atop {y=6}} \right. }}$

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