feliciagraham14
20.09.2021 •
Mathematics
Help me plzz cos5A =16cos^5A-20cos^3A+5cosA
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Ответ:
Step by step explanation :
cos5A=cos(3A+2A)=cos3Acos2A−sin3Asin2A
=(4cos3A−3cosA)(2cos2A−1)−(3sinA−4sin3A)(2sinAcosA)
=(8cos5A−10cos3A+3cosA)−(3−4sin2A)(2sin2AcosA)
=(8cos5A−10cos3A+3cosA)−(3−4(1−cos2A))(2(1−cos2A)cosA)
=(8cos5A−10cos3A+3cosA)−(3−4+4cos2A)(2cosA−2cos3A)
=(8cos5A−10cos3A+3cosA)−(−8cos5A+10cos3A−2cosA)
=16cos5A−20cos3A+5cosA=R.H.S.
Ответ:
y = 6x is your answer.