Help please i need it and u need it explain​

To make it simpler to write (since i can’t cross things out here), combine them first.
numerator : 24(15).x^5.y^8.z^7
denominator: 40(6).x^3.y^6.z^9
First, the numbers.
24(15)/[40(6)] = 3/2
Then x: x^5/x^3 = x^(5-3) = x^2
Then y: y^8/y^6 = y^2
Then z: z^7/z^9 = z^(-2) = 1/z^2
Result: [3.x^2.y^2]/(z^2)

The distance of flag post from Y is 38.13 m

Step-by-step explanation:

Consider point Y at the intersection of both lines as shown below. Now the point X lies 34 meter from point Y in east direction.  

Now flag pole at point X lies at a bearing of N18°W. That is at point X from north, flag post makes an angle of 18° towards west.  

Similarly flag pole at point Y lies at a bearing of N40°E. That is at point Y from north, flag post makes an angle of 40° towards east.  

Consider ∆ AXY as right angle triangle. Therefore measure of angle FXY is,  

Consider ∆ BYX as right angle triangle. Therefore measure of angle FYX is,  

Refer attachment 1.  

From diagram consider the triangle FYX. To find the third angle that is ∠YFX can be calculated by using angle sum property of triangle.

∠YFX+∠FYX+∠FXY=180°

∠YFX+50°+72°=180°

∠YFX=58°

Refer attachment 2.  

Now the distance FY can be calculated using sin rule as follows,  

Substituting the values,

Simplifying first two terms,

Cross multiplying,

m