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anjlieoutar4795
13.07.2021 •
Mathematics
Help solve 4 and 5 please
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Ответ:
Step-by-step explanation:
4). a). If the diagonals of a parallelogram are congruent, then it must be a RECTANGLE.
b). If the diagonals of a parallelogram are perpendicular, then it must be a SQUARE.
c). If the diagonals of a parallelogram bisect the angles of the parallelogram, then it must be a RHOMBUS.
d). If the diagonals of a parallelogram are perpendicular and congruent, then it must be a SQUARE.
e). If a parallelogram has four congruent sides, then it must be a SQUARE.
5). Given quadrilateral SELF is a rhombus.
a). All sides of a rhombus are equal,
Therefore, ES = EL = 25
b). Diagonals of a rhombus bisects the opposite angles,
Therefore, m∠ELS = m∠FLS
3x - 2 = 2x + 7
3x - 2x = 7 + 2
x = 9
c). Diagonals of the rhombus bisect the opposite angles, and adjacent angles are supplementary.
m∠ELF = 2(m∠ELS) = 2(2y - 9)
m∠LES = 2(m∠LEF) = 2(3y + 9)
And 2(2y - 9) + 2(3y + 9) = 180
(2y - 9) + (3y + 9) = 90
5y = 90
y = 18
Ответ:
Pyramid B is 9 times bigger than pyramid A.
Step-by-step explanation:
The formula for determining the volume of a pyramid is expressed as
Volume = 1/3 × base area × height
Considering pyramid A,
base side length = 12 inches
Base area = 12² = 144 inches³
Height = 8 inches
Volume of pyramid A = 1/3 × 144 × 8 = 384 cubic inches
Considering pyramid B,
Volume of pyramid B= 3456 cubic inches
Therefore, the number of times by which pyramid B is bigger than pyramid A would be
3456/384 = 9