HELP WILL GIVE 40 POINTS AND BRAINLIEST Solve these two (second-degree) quadratic equations by factoring. &

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Answer for : x = 0x = -3

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|First we factor out x

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To find equation solutions, solve and

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Answer for :x = -2x = -7

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|To solve the equation, factor using formula To find and , set up a system to be solved.

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Since is positive, and have the same sign. Since is positive, and are both positive. List all such integer pairs that give product 14.

1, 14

2, 7

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Calculate the sum for each pair.

1 + 14 = 15

2 + 7 = 9

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The solution is the pair that gives sum 9.

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Rewrite factored expression using the obtained values.

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To find equation solutions, solve and .

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Step-by-step explanation:

First equation:  2x^2 + 6x = 0 factors into 2x(x + 3) = 0, so either x = 0 or x = -3.

Second equation:  x^2 + 9x + 14 = 0 factors into (x + 2)(x + 7) = 0.  Thus, either x = -2 or x = -7

5)

5 - (49 ÷ 1 - 5) × 2 + 9 - 3
5 - 44 x 2 + 9 - 3
5 - 88 + 9 - 3
-83 + 9 - 3
-74 - 3
= -77

6)

(2 + 76 ÷ 1 + 9) + 4 - 3 × 9
(2 + 76 + 9) + 4 - 3 × 9
87 + 4 - 3 × 9
87 + 4 - 27
91 - 27
= 64

7)

5 × 5 - 7 + 82 ÷ (2 × 1) + 5
5 × 5 - 7 + 82 ÷ 2 + 5
25 - 7 + 82 ÷ 2 + 5
25 - 7 + 41 + 5
18 + 41 + 5
59 + 5
= 64

8)

7 × 7 + 1 + 16 ÷ 8 - (6 - 7)
7 × 7 + 1 + 16 ÷ 8 - 6 + 7
49 + 1 + 16 ÷ 8 - 6 + 7
49 + 1 + 2 - 6 + 7
50 + 2 - 6 + 7
52 - 6 + 7
46 + 7
= 53

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