Mathematics: Help with trig plz 70 pts. plz give a legit answer no guessing

Help with trig plz 70 pts. plz give a legit answer

Ответ:

issaaamiaaa15

20.01.2022

Mathematics

See explanation

Step-by-step explanation:

Use trigonometric functions to solve your problems:

$\cos \theta=\dfrac{\text{Adjacent leg}}{\text{Hypotenuse}}\\ \\\sin \theta=\dfrac{\text{Opposite leg}}{\text{Hypotenuse}}\\ \\\tan \theta=\dfrac{\text{Opposite leg}}{\text{Adjacent leg}}\\ \\\cot \theta=\dfrac{\text{Adjacent leg}}{\text{Opposite leg}}$

Q1. From the diagram,

Adjacent leg AC = 12

Hypotenuse AB = 13

Then $\cos \theta =\dfrac{12}{13}\Rightarrow \theta =\arccos \dfrac{12}{13}\approx 22.6^{\circ}$

Q2. From the diagram,

Adjacent leg AC = 13

Opposite leg BC = 4

Then $\tan \theta =\dfrac{4}{13}\Rightarrow \theta =\arctan \dfrac{4}{13}\approx 17.1^{\circ}$

Q3. From the diagram,

Adjacent leg AC = 6

Hypotenuse AB = 9

Then $\cos \theta =\dfrac{6}{9}\Rightarrow \theta =\arccosn \dfrac{6}{9}\approx 48.2^{\circ}$

Q4. From the diagram,

Adjacent leg AC = 10

Opposite leg BC = 11.9

Then $\tan \theta =\dfrac{11.9}{10}\Rightarrow \theta =\arctan \dfrac{11.9}{10}\approx 50^{\circ}$

Q5. From the diagram,

Adjacent leg BC = 14

Opposite leg AC = 7.7

Then $\tan \theta =\dfrac{7.7}{14}\Rightarrow \theta =\arctan \dfrac{7.7}{14}\approx 28.8^{\circ}$

Q6. From the diagram,

Adjacent leg BC = 4

Hypotenuse AB = 5

Then $\cos \theta =\dfrac{4}{5}\Rightarrow \theta =\arccosn \dfrac{4}{5}\approx 36.9^{\circ}$

Q7. From the diagram,

Adjacent leg BC = 4.4

Hypotenuse AB = 11

Then $\cos \theta =\dfrac{4.4}{11}\Rightarrow \theta =\arccosn \dfrac{4.4}{11}\approx 66.4^{\circ}$

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Help with trig plz 70 pts. plz give a legit answer no guessing

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