HELPP!! The transformation functions R, S, T, U, and V are shown below

Point T(x, y) is translated 71 units up and then rotated 180° about the origin

Point U(x, y) is rotated 90° counterclockwise, then translated 124 units up.

Point V(x, y) is reflected about the y axis, then translated 8831 units to the left.

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, translation and dilation.

If a point R(x, y) is vertical stretched by a factor of 38 followed by a horizontal stretch of 7, the new point is at R'(x/7, 38y). That is (x, y) ⇒ (x/7, 38y).

If a point S(x, y) is translated 9 units to the right, the new point is (x + 9, y), if it is reflected over the y axis, the new point is S'(-x-9, y). That is (x, y) ⇒ (-x-9, y).

If a point T(x, y) is translated 71 units up, the new point is at (x, y + 71), if it is rotated 180° about the origin, the new point is at T'(-x, -y - 71). That is (x, y) ⇒ (-x, -y - 71).

If a point U(x, y) is rotated 90° counterclockwise, the new point is at (-y, x), if it is then translated 124 units up, the new point is U'(-y, x + 124).

If a point V(x, y) is reflected about the y axis, the new point is at (-x, y), if it is then translated 8831 units to the left, the new point is V'(-x - 8831, y).

 See below

Step-by-step explanation:

4) You made an error in step 3

Step 1: -x³ + 22x² - 121x = 0

Step 2: -x(x² - 22x + 121) = 0

Step 3: -x(x - 11²) = 0       Error!

           -x(x - 11)² = 0        Correction

Step 4: -x = 0     (x - 11)² = 0

Step 5:    x = 0      x = 11

15) Your work is correct

    n = 8, n = -9      BOTH answers are correct

n = 8      Error!  

              n = 8, n = -9    Correction

18) The formula is: h(t) =at² + vt + h(0)

h(t) = -4.9t² + 24.5t + 117.6      option 3

19) Now that you have the correct equation, you can use the quadratic formula to solve for t

t = -3, t = 8

Since time cannot be negative, t = -3 is not valid

t = 8    option 1

20) It is given that h(t) = 49

Equation: 49 = -4.9t² + 24.5t + 117.6

                 0 = -4.9t² + 24.5t + 68.6

Use the quadratic equation to solve: t = -2, t = 7

Since time cannot be negative, t = -2 is not valid

t =7