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lexi7752
17.12.2020 •
Mathematics
HELPPPP PLEASEEEEEE
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Ответ:
does not exist
explanationthe denominator is 0 when p is substituted by 1, so we cannot use the quotient limit law
if you attempted to multiply by the conjugate (of either the numerator or denominator), you would not get anywhere useful.
so let us check the left- and right- hand limits. the two-sided limit exists if and only if the one-sided limits (from the left and from the right) exist and are equal to each other.
consider the limit
if p approaches 1 but is less than one
, then the numerator approaches
while the denominator approaches a small positive number (since
. so we have that the quotient becomes a large positive number and so ![\lim_{p \to 1^-} \frac{1+\sqrt{p}}{1 - \sqrt{p}} = \infty](/tex.php?f=\lim_{p \to 1^-} \frac{1+\sqrt{p}}{1 - \sqrt{p}} = \infty)
if p approaches 1 but is greater than 1
, then the numerator approaches
while the denominator approaches a small negative number (since
). we have that the quotient becomes a large negative number and so ![\lim_{p \to 1^+} \frac{1+\sqrt{p}}{1 - \sqrt{p}} = -\infty](/tex.php?f=\lim_{p \to 1^+} \frac{1+\sqrt{p}}{1 - \sqrt{p}} = -\infty)
the left- and right-hand limits are different, so the limit does not exist