tatielder4896
17.01.2020 •
Mathematics
Hexagon ijklmn is shown on the coordinate plane below:
hexagon ijklmn on a coordinate plane with ordered pairs at i negative two, six, at j four, four, at k six, negative one at, l n
if hexagon ijklmn is dilated by a scale factor of two fifths from the origin to create hexagon i'j'k'l'm'n', what is the ordered pair of point i'? (4 points)
a) (−0.8, 2.4)
b) (−5, 15)
c) (−2.5, 5)
d) (−0.4, 0.8)
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Ответ:
Option: A is the correct answer.
The ordered pair of point I' are:
A) (-0.8,2.4)
Step-by-step explanation:We know than if any point A with vertices as (a,b) are dilated by a scale factor of k then the vertices of the transformed point is:
A(a,b) → A'(ka,kb)
We are given vertices of point I as:
I(-2,6)
Hence, the vertices of the transformed point I' after dilating by a scale factor of 2/5 is:
I(-2,6) → I'(-2×(2/5),6×(2/5))
⇒ I(-2,6) → I'(-0.8,2.4)
Hence, option: A is the answer.
A) (-0.8,2.4)
Ответ:
(-0.8,2.4)
Step-by-step explanation:
We know than if any point (a,b) are dilated by a scale factor of k from the origin then the vertices of the image point is :
Given : Hexagon IJKLMN on a coordinate plane with ordered pairs at I (-2,6).
Then, the coordinates of the image point I' after dilating by a scale factor of will be :
Hence, the ordered pair of point I' =(-0.8, 2.4)
Ответ:
96 inches
Step-by-step explanation:
8 ft is 8(12) inches, which is 96 inches