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jamessmith86
08.12.2019 •
Mathematics
Hi, would appreciate the will mark brainliest : )
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Ответ:
#1
Yes, it's a rhombus. A square is a rhombus but a rhombus is not necessarily a square.
For every rhombus, the diagonals are perpendicular and each one bisects the other.
#2
The midpoints of the sides are:
M ( (2a+0)/2 , (2b+0)/2 ) = ( a , b )
N ( (-2a+0)/2 , (2b+0)/2 ) = ( - a, b )
P ( (-2a+0)/2, ( -2b+0)/2 ) = ( - a, - b )
Q ( (2 a+0)/2) , (-2b+0)/2 ) = ( a , - b )
The midpoints of a rhombus determine a rectangle.
Ответ:
its still a rhombus because it has two acute triangles and that normally makes a rhombus :)
the second one is pretty hard but what you can do is go to mathay and write down the problem! :)
hope this helps
plz make me brainliest
Ответ: