Hiroki and Mapiya were asked to find an explicit

Ответ:

lalaokawami0912

22.11.2020

Mapiya's explicit formula : $f(n)=125\cdot\left(\dfrac{1}{5}\right)^{\large{n}}$ is right

Step-by-step explanation:

Sequence : 125,25,5,1,..

Hiroki's explicit formula : $f(n)=625\cdot\left(\dfrac{1}{5}\right)^{\large{n}}$

Mapiya's explicit formula : $f(n)=125\cdot\left(\dfrac{1}{5}\right)^{\large{n}}$

Formula of sequence= a(r)^n

a = First term

n = No. of terms

r=Common ratio

a=125

$r = \frac{25}{125}=\frac{5}{25}=\frac{1}{5}$

So, $a(r)^n=125(\frac{1}{5})^n$

Hence Mapiya's explicit formula : $f(n)=125\cdot\left(\dfrac{1}{5}\right)^{\large{n}}$ is right

0,0(0 оценок)